Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8

Answer:18y=14x+334 ory=0.25x+8.25 or4y=x+33Explanation:.y−3=−4(x+2)Let's get this equation into the standard slope-intercept form of:y=mx+b where m is the slope and b is the y-intercept.y=−4(x+2)+3y=−4x−8+3y=−4x−5Let's call the slope of this line m1 and the slope of the line perpendicular to it m2 .m1=−4In order for the other line to be perpendicular to this one we have to have:m1m2=−1−4m2=−1m2=−1−4=14Now, we cam write the equation of the perpendicular line:y=14x+bWe can now use the coordinates of the point this line goes through to find b:7=14(−5)+b7=−54