A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor of 36 N. Find the acceleration of the box in m/s2 Show your work
Accepted Solution
A:
The net force is what remains of the pull when we subtract the friction force:[tex]F = 64-36 = 28N[/tex]Now, use the law[tex]F=ma[/tex]and solve it for the acceleration[tex]a = \dfrac{F}{m}[/tex]to get the result:[tex]a = \dfrac{28}{14}=2[/tex]